25 式と乗法公式

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25 式と乗法公式
1
2
/
次の計算をしなさい。
(1) 3a(a+2b)=
(2) -3b(5a-3b)=
(3) (2x+y)×(-6y)=
(4)
(5) 2x(x+y-z)=
(6) (3a-2b-4)×(-5a) =
2
5
x(10x-5)=
次の計算をしなさい。
(1) (a2b+2ab)÷a=
3
(2) (8x2y+4y)÷(-2y)=
(3) (6ab+3a2b)÷ b=
(4) (10xy2-5x2y)÷5xy=
(5) (ab+ac-a)÷a=
(6) (4ab-2a2b-4ab2)÷(- ab)=
2
2
7
3
次の計算をしなさい。
(1) 3a(a-4)+2a(a+1)=
(2) 2x(4x-2y)-4x(5x-y)=
(3) -a(2a+b)-7a(a-6b)=
(4)
3
4
a(5a-2)+3a(a+3)=
1
(5) x(2x-3y+z)+ x(3y+6z)=
6
4
次の計算をしなさい。
(1) (x+2)(y+5)=
(2) (a-3b)(c+2d)=
(3) (a+1)(a-6)=
(4) (2a+b)(a+4b)=
(5) (3x-2)(5x-3)=
(6) (a+2)(a+b+1)=
(7) (a+2)(a+b+1)=
5
次の計算をしなさい。
(1) (x+3)(x+2)=
(2) (x+3)(x-1)=
(3) (a-1)(a-7)=
(4) (y+2)(y+4)=
(5) (b-3)(b-9)=
(6) (x+ )(x+ )=
(7) (x-
6
2
3
1
)(x+ )=
3
1
5
6
6
(8) (3+x)(-2+x)=
次の計算をしなさい。
(1) (x+3)2 =
(2) (y-2)2 =
(3) (a+1)2 =
(4) (a-9)2 =
(5) (x+
1
2
2
) =
(7) (-a+2)2 =
(6) (5-x)2 =
(8) (-x-6)2 =
7
8
次の計算をしなさい。
(1) (x+2)(x-2)=
(2) (a+3)(a-3)=
(3) (a+b)(a-b)=
(4) (y-2)(y+2)=
(5) (b-1)(b+1)=
(6) (x+ )(x-
(7) (x+5)(5-x)=
(8) (-8+b)(b+8)=
1
1
2
2
)=
次の計算をしなさい。
(1) (x-7)(x+7)=
(2) (x+6)(x-8)=
(3) (b-8)2 =
(4) (y+2)(5+y)=
1
(5) (b+ ) =
(6) (-2+a)(2+a)=
(7) (x+7)2 =
(8) (x-5)(x+10)=
2
2
答え
1 (1) 3a2 +3ab, (2) -15ab+9b2 , (3) -12xy-6y 2, (4) 4x 2-2x, (5) 2x 2+2xy-2xz, (6) -15a2 +10ab+20a,
2 (1) ab+2b, (2) -4x 2-2, (3) 4a+2a2 , (4) 2y-x, (5) b+c-1, (6) 7a+14b-14
27 2 15
5
a + a , (5) 2x 2- xy+2xz
4
2
2
2
2
(3) a -5a-6, (4) 2a +9ab+4b2 ,
3 (1) 5a2 -10a, (2) -12x 2, (3) -9a2 +41ab, (4)
4 (1) xy+5x+2y+10, (2) ac+2ad-3bc-6bd,
(5) 15x 2-19x+6,
(6) a2 +ab+3a+2b+2, (7) a2 +ab+3a+2b+2
5 (1) x 2+5x+6, (2) x 2+2x-3, (3) a2 -8a+7, (4) y 2+6y+8, (5) b2 -12b+27, (6) x 2+x+
1
2
3
9
5
,
36
(7) x 2- x - , (8) x 2+x-6
1
6 (1) x +6x+9, (2) y 2-4y+4, (3) a2 +2ax+1, (4) a2 -18a+81, (5) x 2+x+ ,
2
4
(6) x 2-10x+25
(7) a2 -4a+4, (8) x 2+12x+36
1
7 (1) x 2-4, (2) a2 -9, (3) a2 -b2 , (4) y 2-4, (5) b2 -1, (6) x 2- , (7) -x 2+25, (8) b2 -64
4
1
8 (1) x 2-49, (2) x 2-2x-48, (3) b2 -16b+64, (4) y 2+7y+10, (5) b2 +b+ , (6) a2 -4
(7) x 2+14x+49, (8)x 2+5x-50
4